Hi i want to build a custom chassis with a rumble motor a crystal chaber with pixel rgb accent nd a rgb baselit led all that in a removable chassis with pogo pin all i need is to know where to solder the motor to control it with the blade type that the rgb led is set to like pulse and unstable or stable i found this thread for the code im really new to coding so i dont know if it would work also im not vey experience in doing my own diagram for wiring ive done a tone of electronic project but always with a diagram already done so im really lost
Have you tried the configuration generator to help with the diagram?
Yes it doesnt have option for motor but everithing else is there
If you add a second blade in the config generator it wires like that according to the thread you linked to. Just about everything you need is there 
Thanks i was really i was very dissapoited to not find any diagram now i have one d can build my saber when my parts arrives
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One last question what type of resistor d i need for that motor
https://www.amazon.ca/-/fr/gp/aw/d/B08HN382WR?psc=1&ref=ppx_pop_mob_b_asin_title
Because ive already have one of those laying around and was thinking to use it for my crystal chamber after removing the reduction gear box
I’d use ohm’s law I suppose. Running at 1 Amp, 3volts. R=V/I so 3 ohms for power?
And what wattage do i need the resistor to be
Regurged from the ol’ FX Forum circa 2016, which quoted a TCSS forum post even before that. (yes you’re playing with 10 year old concepts
Ohm’s Law - the down and dirty guide to “Doing the Math” yourself.
Ohm’s Law comes in two parts, meaning there are two values you need to calculate. The “Ohms” value and the “Watts” value. The formulas for both are as follows:
R = \frac{V_f^\text{Battery} - (V_f^\text{LED1} + V_f^\text{LED2})}{I}
Where:
Vf Battery = Battery Voltage (usually either 3.7V or 7.4V)
Vf LED1 = Forward Voltage of LED #1
Vf LED2 = Forward Voltage of LED #2 (If you have a second in series)
I = (in Amps) Current you wish to run your LED at (Reds and Red-Oranges are usually 700 mA and Blues, Greens and Whites are usually 1A)
The second part of the formula is as follows:
P = R \cdot I^2
Where:
- ( R ) = the resistance value from the first calculation
- ( I ) = Current you wish to run your LED at (in Amps) (Reds and Red-Oranges are usually 700 mA and Blues, Greens and Whites are usually 1A) - This value needs to be squared in your calculation.
In the following example, I calculate a resistor value for a single Red LED
(Vf= 2.4V) running at 700mA running it off of a 3.7V battery.
R = \frac{3.7 - 2.4}{0.7} \Rightarrow \frac{1.3}{0.7} \Rightarrow 1.86 \Rightarrow \text{Rounded up to 2 Ohms}
P = R \cdot I^2 \Rightarrow 1.86 \cdot (0.7)^2 \Rightarrow 0.91W \Rightarrow \text{Rounded up to 1W}
Since there are only so many values that are commonly produced, it will be very likely that you will need to round UP to the next resistor size, to get the resistor that you would need (and as I did in the above example).
So, I will need a 2 Ohm, 1W resistor.
I’m a bit confused about this motor.
I see 6VDC in the table, but is that for the same motor, or for a different one?
If the motor can handle 6 volts, then you don’t need a resistor.
This is not how you use ohm’s law. Sorry about that. There’s a section on it right on the Proffie V3 page. It’s ofcourse saying the same thing as the previous post on the topic but it was a bit easier for me to read.
You can do the math, hopefully better than me
I belive i have the 6v option because it can go to 70rpm and the table say 6v for that speed
Well hopefully it will also run happily on 3.7v (without a resistor).
Thanks for the help